Search a number
-
+
23500045143121 = 43546512677747
BaseRepresentation
bin1010101011111100001111…
…10101111100110001010001
310002012120201112220000001211
411111332013311330301101
511040011043024034441
6121551434404300121
74643552011614061
oct525760765746121
9102176645800054
1023500045143121
117540349924978
1227765716a1641
1310160774091c1
145b35a03693a1
152ab454178a81
hex155f87d7cc51

23500045143121 has 4 divisors (see below), whose sum is σ = 24046557820912. Its totient is φ = 22953532465332.

The previous prime is 23500045142941. The next prime is 23500045143131. The reversal of 23500045143121 is 12134154000532.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23500045143121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23500045143131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273256338831 + ... + 273256338916.

It is an arithmetic number, because the mean of its divisors is an integer number (6011639455228).

Almost surely, 223500045143121 is an apocalyptic number.

It is an amenable number.

23500045143121 is a deficient number, since it is larger than the sum of its proper divisors (546512677791).

23500045143121 is an equidigital number, since it uses as much as digits as its factorization.

23500045143121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 546512677790.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 23500045143121 its reverse (12134154000532), we get a palindrome (35634199143653).

The spelling of 23500045143121 in words is "twenty-three trillion, five hundred billion, forty-five million, one hundred forty-three thousand, one hundred twenty-one".

Divisors: 1 43 546512677747 23500045143121