Base | Representation |
---|---|
bin | 110101011100011011101010… |
… | …011110010011101100100001 |
3 | 1010211020120221112012201210020 |
4 | 311130123222132103230201 |
5 | 221302031020344220213 |
6 | 2151524342410024053 |
7 | 100336552621125423 |
oct | 6534335236235441 |
9 | 1124216845181706 |
10 | 235050314054433 |
11 | 68992307597729 |
12 | 224423aa718029 |
13 | a1201c3611017 |
14 | 42086d2a78813 |
15 | 1c292e87b7923 |
hex | d5c6ea793b21 |
235050314054433 has 4 divisors (see below), whose sum is σ = 313400418739248. Its totient is φ = 156700209369620.
The previous prime is 235050314054389. The next prime is 235050314054461. The reversal of 235050314054433 is 334450413050532.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 235050314054433 - 217 = 235050313923361 is a prime.
It is not an unprimeable number, because it can be changed into a prime (235050214054433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39175052342403 + ... + 39175052342408.
It is an arithmetic number, because the mean of its divisors is an integer number (78350104684812).
Almost surely, 2235050314054433 is an apocalyptic number.
It is an amenable number.
235050314054433 is a deficient number, since it is larger than the sum of its proper divisors (78350104684815).
235050314054433 is an equidigital number, since it uses as much as digits as its factorization.
235050314054433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78350104684814.
The product of its (nonzero) digits is 1296000, while the sum is 42.
The spelling of 235050314054433 in words is "two hundred thirty-five trillion, fifty billion, three hundred fourteen million, fifty-four thousand, four hundred thirty-three".
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