Base | Representation |
---|---|
bin | 1101110110110001111… |
… | …1100111010100110011 |
3 | 211202102122201001222201 |
4 | 3131230133213110303 |
5 | 12400003104200042 |
6 | 301204452444031 |
7 | 23124636516460 |
oct | 3355437472463 |
9 | 752378631881 |
10 | 238043428147 |
11 | 91a54344908 |
12 | 3a174319617 |
13 | 195a7c213c5 |
14 | b74289a667 |
15 | 62d32c61b7 |
hex | 376c7e7533 |
238043428147 has 8 divisors (see below), whose sum is σ = 273178470752. Its totient is φ = 203190595200.
The previous prime is 238043428099. The next prime is 238043428157. The reversal of 238043428147 is 741824340832.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 238043428147 - 211 = 238043426099 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 238043428097 and 238043428106.
It is not an unprimeable number, because it can be changed into a prime (238043428157) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70550604 + ... + 70553977.
It is an arithmetic number, because the mean of its divisors is an integer number (34147308844).
Almost surely, 2238043428147 is an apocalyptic number.
238043428147 is a deficient number, since it is larger than the sum of its proper divisors (35135042605).
238043428147 is a wasteful number, since it uses less digits than its factorization.
238043428147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141104829.
The product of its (nonzero) digits is 1032192, while the sum is 46.
Adding to 238043428147 its reverse (741824340832), we get a palindrome (979867768979).
The spelling of 238043428147 in words is "two hundred thirty-eight billion, forty-three million, four hundred twenty-eight thousand, one hundred forty-seven".
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