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2387054629441 = 9103262227247
BaseRepresentation
bin100010101111000111100…
…010110001001001000001
322110012101221102021000001
4202233013202301021001
5303102141441120231
65024333041000001
7334313303366656
oct42570742611101
98405357367001
102387054629441
11840387120729
12326763923001
13144137c1a321
1483769667c2d
154215d165b61
hex22bc78b1241

2387054629441 has 4 divisors (see below), whose sum is σ = 2387316865792. Its totient is φ = 2386792393092.

The previous prime is 2387054629433. The next prime is 2387054629457. The reversal of 2387054629441 is 1449264507832.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2387054629441 - 23 = 2387054629433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2387054629411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131104521 + ... + 131122726.

It is an arithmetic number, because the mean of its divisors is an integer number (596829216448).

It is a 1-persistent number, because it is pandigital, but 2⋅2387054629441 = 4774109258882 is not.

Almost surely, 22387054629441 is an apocalyptic number.

It is an amenable number.

2387054629441 is a deficient number, since it is larger than the sum of its proper divisors (262236351).

2387054629441 is an equidigital number, since it uses as much as digits as its factorization.

2387054629441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262236350.

The product of its (nonzero) digits is 11612160, while the sum is 55.

The spelling of 2387054629441 in words is "two trillion, three hundred eighty-seven billion, fifty-four million, six hundred twenty-nine thousand, four hundred forty-one".

Divisors: 1 9103 262227247 2387054629441