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2401213101113 = 2423299908897
BaseRepresentation
bin100010111100010011011…
…101000011010000111001
322111112221200002010211202
4202330103131003100321
5303320141023213423
65035034014103545
7335324204411021
oct42742335032071
98445850063752
102401213101113
11846392217a92
123294554aabb5
13145583303108
148430dbd2a81
15426db14d728
hex22f13743439

2401213101113 has 4 divisors (see below), whose sum is σ = 2401223252340. Its totient is φ = 2401202949888.

The previous prime is 2401213101073. The next prime is 2401213101121. The reversal of 2401213101113 is 3111013121042.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 527303988649 + 1873909112464 = 726157^2 + 1368908^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2401213101113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2401213101173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4712120 + ... + 5196777.

It is an arithmetic number, because the mean of its divisors is an integer number (600305813085).

Almost surely, 22401213101113 is an apocalyptic number.

It is an amenable number.

2401213101113 is a deficient number, since it is larger than the sum of its proper divisors (10151227).

2401213101113 is an equidigital number, since it uses as much as digits as its factorization.

2401213101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10151226.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 2401213101113 its reverse (3111013121042), we get a palindrome (5512226222155).

The spelling of 2401213101113 in words is "two trillion, four hundred one billion, two hundred thirteen million, one hundred one thousand, one hundred thirteen".

Divisors: 1 242329 9908897 2401213101113