241011131041235 has 4 divisors (see below), whose sum is σ = 289213357249488. Its totient is φ = 192808904832984.

The previous prime is 241011131041211. The next prime is 241011131041249. The reversal of 241011131041235 is 532140131110142.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 241011131041235 - 2¹² = 241011131037139 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 241011131041198 and 241011131041207.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24101113104119 + ... + 24101113104128.

It is an arithmetic number, because the mean of its divisors is an integer number (72303339312372).

Almost surely, 2^{241011131041235} is an apocalyptic number.

241011131041235 is a deficient number, since it is larger than the sum of its proper divisors (48202226208253).

241011131041235 is an equidigital number, since it uses as much as digits as its factorization.

241011131041235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48202226208252.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 241011131041235 its reverse (532140131110142), we get a palindrome (773151262151377).

The spelling of 241011131041235 in words is "two hundred forty-one trillion, eleven billion, one hundred thirty-one million, forty-one thousand, two hundred thirty-five".