Base | Representation |
---|---|
bin | 100011000110011100010… |
… | …111110001101001010011 |
3 | 22112121001101221120210010 |
4 | 203012130113301221103 |
5 | 304004440113201121 |
6 | 5044034205010003 |
7 | 336161042553105 |
oct | 43063427615123 |
9 | 8477041846703 |
10 | 2412100131411 |
11 | 84aa69705a93 |
12 | 32b593553903 |
13 | 1465c99c5789 |
14 | 84a63a97575 |
15 | 42b26d25376 |
hex | 2319c5f1a53 |
2412100131411 has 8 divisors (see below), whose sum is σ = 3355965400320. Its totient is φ = 1538150808392.
The previous prime is 2412100131379. The next prime is 2412100131509. The reversal of 2412100131411 is 1141310012142.
2412100131411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2412100131411 - 25 = 2412100131379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2412100131211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17478986391 + ... + 17478986528.
It is an arithmetic number, because the mean of its divisors is an integer number (419495675040).
Almost surely, 22412100131411 is an apocalyptic number.
2412100131411 is a deficient number, since it is larger than the sum of its proper divisors (943865268909).
2412100131411 is a wasteful number, since it uses less digits than its factorization.
2412100131411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34957972945.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 2412100131411 its reverse (1141310012142), we get a palindrome (3553410143553).
The spelling of 2412100131411 in words is "two trillion, four hundred twelve billion, one hundred million, one hundred thirty-one thousand, four hundred eleven".
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