Search a number
-
+
24131055013099 = 71339874014269
BaseRepresentation
bin1010111110010011100101…
…11101100100110011101011
310011102220110201021200002221
411133021302331210303223
511130330400040404344
6123153353103534511
75040261016200226
oct537116275446353
9104386421250087
1024131055013099
117763a17506791
1228589155ba437
1310607197132a8
145d5d40c145bd
152bca86601184
hex15f272f64ceb

24131055013099 has 4 divisors (see below), whose sum is σ = 24470929027440. Its totient is φ = 23791180998760.

The previous prime is 24131055013081. The next prime is 24131055013127. The reversal of 24131055013099 is 99031055013142.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 24131055013099 - 25 = 24131055013067 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (24131055010099) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169937007064 + ... + 169937007205.

It is an arithmetic number, because the mean of its divisors is an integer number (6117732256860).

Almost surely, 224131055013099 is an apocalyptic number.

24131055013099 is a deficient number, since it is larger than the sum of its proper divisors (339874014341).

24131055013099 is an equidigital number, since it uses as much as digits as its factorization.

24131055013099 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339874014340.

The product of its (nonzero) digits is 145800, while the sum is 43.

Adding to 24131055013099 its sum of digits (43), we get a palindrome (24131055013142).

The spelling of 24131055013099 in words is "twenty-four trillion, one hundred thirty-one billion, fifty-five million, thirteen thousand, ninety-nine".

Divisors: 1 71 339874014269 24131055013099