Base | Representation |
---|---|
bin | 100011000111101010000… |
… | …011010111100001111011 |
3 | 22112201102020021201020111 |
4 | 203013222003113201323 |
5 | 304020122232420121 |
6 | 5044411402405151 |
7 | 336235246314616 |
oct | 43075203274173 |
9 | 8481366251214 |
10 | 2413403404411 |
11 | 85057833930a |
12 | 32b897b007b7 |
13 | 146776a0842c |
14 | 84b48bcb17d |
15 | 42ba14602e1 |
hex | 231ea0d787b |
2413403404411 has 4 divisors (see below), whose sum is σ = 2419771223800. Its totient is φ = 2407035585024.
The previous prime is 2413403404343. The next prime is 2413403404427. The reversal of 2413403404411 is 1144043043142.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2413403404411 - 213 = 2413403396219 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2413403404441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3183909126 + ... + 3183909883.
It is an arithmetic number, because the mean of its divisors is an integer number (604942805950).
Almost surely, 22413403404411 is an apocalyptic number.
2413403404411 is a deficient number, since it is larger than the sum of its proper divisors (6367819389).
2413403404411 is an equidigital number, since it uses as much as digits as its factorization.
2413403404411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6367819388.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 2413403404411 its reverse (1144043043142), we get a palindrome (3557446447553).
The spelling of 2413403404411 in words is "two trillion, four hundred thirteen billion, four hundred three million, four hundred four thousand, four hundred eleven".
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