Base | Representation |
---|---|
bin | 110110111000000001001001… |
… | …110001111101011001010011 |
3 | 1011122112021011010011221020211 |
4 | 312320001021301331121103 |
5 | 223113140043233131011 |
6 | 2213143531010144551 |
7 | 101556350205106621 |
oct | 6670011161753123 |
9 | 1148467133157224 |
10 | 241344040130131 |
11 | 6a999483911174 |
12 | 2309a112882157 |
13 | a488850a35873 |
14 | 4385184654511 |
15 | 1cd7da4218b21 |
hex | db8049c7d653 |
241344040130131 has 16 divisors (see below), whose sum is σ = 251930415179520. Its totient is φ = 230932771914240.
The previous prime is 241344040130113. The next prime is 241344040130147. The reversal of 241344040130131 is 131031040443142.
241344040130131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 241344040130131 - 27 = 241344040130003 is a prime.
It is a super-2 number, since 2×2413440401301312 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 241344040130093 and 241344040130102.
It is not an unprimeable number, because it can be changed into a prime (241344040130101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 521100895 + ... + 521563831.
It is an arithmetic number, because the mean of its divisors is an integer number (15745650948720).
Almost surely, 2241344040130131 is an apocalyptic number.
241344040130131 is a deficient number, since it is larger than the sum of its proper divisors (10586375049389).
241344040130131 is a wasteful number, since it uses less digits than its factorization.
241344040130131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652014.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 241344040130131 its reverse (131031040443142), we get a palindrome (372375080573273).
The spelling of 241344040130131 in words is "two hundred forty-one trillion, three hundred forty-four billion, forty million, one hundred thirty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •