Base | Representation |
---|---|
bin | 100011000111101100010… |
… | …011001101000110000011 |
3 | 22112201111212020101010201 |
4 | 203013230103031012003 |
5 | 304020211411013103 |
6 | 5044415230510031 |
7 | 336236214646621 |
oct | 43075423150603 |
9 | 8481455211121 |
10 | 2413441110403 |
11 | 850597652394 |
12 | 32b8a8665317 |
13 | 14678177aa7b |
14 | 84b4dc04511 |
15 | 42ba490c51d |
hex | 231ec4cd183 |
2413441110403 has 8 divisors (see below), whose sum is σ = 2609125525520. Its totient is φ = 2224622815200.
The previous prime is 2413441110371. The next prime is 2413441110413. The reversal of 2413441110403 is 3040111443142.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2413441110403 - 25 = 2413441110371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2413441110413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1716529248 + ... + 1716530653.
It is an arithmetic number, because the mean of its divisors is an integer number (326140690690).
Almost surely, 22413441110403 is an apocalyptic number.
2413441110403 is a deficient number, since it is larger than the sum of its proper divisors (195684415117).
2413441110403 is a wasteful number, since it uses less digits than its factorization.
2413441110403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3433059957.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 2413441110403 its reverse (3040111443142), we get a palindrome (5453552553545).
The spelling of 2413441110403 in words is "two trillion, four hundred thirteen billion, four hundred forty-one million, one hundred ten thousand, four hundred three".
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