Base | Representation |
---|---|
bin | 1010111110111010111001… |
… | …11011010000001100100001 |
3 | 10011111220221120022022100220 |
4 | 11133131130323100030201 |
5 | 11131202110444021423 |
6 | 123211203232033253 |
7 | 5041636020631503 |
oct | 537353473201441 |
9 | 104456846268326 |
10 | 24152160142113 |
11 | 7771967833573 |
12 | 2860a25692829 |
13 | 1062701046303 |
14 | 5d6d83bb1d73 |
15 | 2bd3be3b79e3 |
hex | 15f75ced0321 |
24152160142113 has 16 divisors (see below), whose sum is σ = 32551222020096. Its totient is φ = 15927612377040.
The previous prime is 24152160142081. The next prime is 24152160142207. The reversal of 24152160142113 is 31124106125142.
It is not a de Polignac number, because 24152160142113 - 25 = 24152160142081 is a prime.
It is a super-3 number, since 3×241521601421133 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (24152160142213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42617695 + ... + 43180692.
It is an arithmetic number, because the mean of its divisors is an integer number (2034451376256).
Almost surely, 224152160142113 is an apocalyptic number.
It is an amenable number.
24152160142113 is a deficient number, since it is larger than the sum of its proper divisors (8399061877983).
24152160142113 is a wasteful number, since it uses less digits than its factorization.
24152160142113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85799404.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 24152160142113 its reverse (31124106125142), we get a palindrome (55276266267255).
The spelling of 24152160142113 in words is "twenty-four trillion, one hundred fifty-two billion, one hundred sixty million, one hundred forty-two thousand, one hundred thirteen".
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