2415313000001 has 4 divisors (see below), whose sum is σ = 2634886909104. Its totient is φ = 2195739090900.

The previous prime is 2415312999881. The next prime is 2415313000057. The reversal of 2415313000001 is 1000003135142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2415313000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2415313000081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109786954535 + ... + 109786954556.

It is an arithmetic number, because the mean of its divisors is an integer number (658721727276).

Almost surely, 2^{2415313000001} is an apocalyptic number.

It is an amenable number.

2415313000001 is a deficient number, since it is larger than the sum of its proper divisors (219573909103).

2415313000001 is a wasteful number, since it uses less digits than its factorization.

2415313000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219573909102.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 2415313000001 its reverse (1000003135142), we get a palindrome (3415316135143).

The spelling of 2415313000001 in words is "two trillion, four hundred fifteen billion, three hundred thirteen million, one", and thus it is an aban number.