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242013461000161 = 770537314084153
BaseRepresentation
bin110111000001110000100110…
…010111111010111111100001
31011201220021001012122120122111
4313001300212113322333201
5223210122032004001121
62214415241002435321
7101655616113450004
oct6701604627727741
91151807035576574
10242013461000161
1170127372502924
12231879b6502b41
13a506a04b3b256
1443a972a63b53b
151cea4d38ed2e1
hexdc1c265fafe1

242013461000161 has 4 divisors (see below), whose sum is σ = 242013775854852. Its totient is φ = 242013146145472.

The previous prime is 242013461000071. The next prime is 242013461000191. The reversal of 242013461000161 is 161000164310242.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 231164079054561 + 10849381945600 = 15204081^2 + 3293840^2 .

It is a cyclic number.

It is not a de Polignac number, because 242013461000161 - 213 = 242013460991969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (242013461000191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156271540 + ... + 157812613.

It is an arithmetic number, because the mean of its divisors is an integer number (60503443963713).

Almost surely, 2242013461000161 is an apocalyptic number.

It is an amenable number.

242013461000161 is a deficient number, since it is larger than the sum of its proper divisors (314854691).

242013461000161 is an equidigital number, since it uses as much as digits as its factorization.

242013461000161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 314854690.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 242013461000161 in words is "two hundred forty-two trillion, thirteen billion, four hundred sixty-one million, one hundred sixty-one", and thus it is an aban number.

Divisors: 1 770537 314084153 242013461000161