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242110300433 = 358367571951
BaseRepresentation
bin1110000101111011100…
…1100000000100010001
3212010221002020120222012
43201132321200010101
512431320214103213
6303120211552305
723330501412131
oct3413671400421
9763832216865
10242110300433
1193750a53191
123ab0a2bb695
1319aa5657b01
14ba0aa5aac1
15647035a4a8
hex385ee60111

242110300433 has 4 divisors (see below), whose sum is σ = 242177875968. Its totient is φ = 242042724900.

The previous prime is 242110300427. The next prime is 242110300451. The reversal of 242110300433 is 334003011242.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-242110300433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 242110300399 and 242110300408.

It is not an unprimeable number, because it can be changed into a prime (242110360433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33782393 + ... + 33789558.

It is an arithmetic number, because the mean of its divisors is an integer number (60544468992).

Almost surely, 2242110300433 is an apocalyptic number.

It is an amenable number.

242110300433 is a deficient number, since it is larger than the sum of its proper divisors (67575535).

242110300433 is an equidigital number, since it uses as much as digits as its factorization.

242110300433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67575534.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 242110300433 its reverse (334003011242), we get a palindrome (576113311675).

The spelling of 242110300433 in words is "two hundred forty-two billion, one hundred ten million, three hundred thousand, four hundred thirty-three".

Divisors: 1 3583 67571951 242110300433