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242135531241 = 380711843747
BaseRepresentation
bin1110000110000001100…
…1101111111011101001
3212010222211201110010120
43201200121233323221
512431343143444431
6303122512433453
723331226025262
oct3414031577351
9763884643116
10242135531241
119376421649a
123ab16848889
1319aaa950096
14ba10147969
156472691196
hex386066fee9

242135531241 has 4 divisors (see below), whose sum is σ = 322847374992. Its totient is φ = 161423687492.

The previous prime is 242135531219. The next prime is 242135531243. The reversal of 242135531241 is 142135531242.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-242135531241 is a prime.

It is a super-2 number, since 2×2421355312412 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (242135531243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40355921871 + ... + 40355921876.

It is an arithmetic number, because the mean of its divisors is an integer number (80711843748).

Almost surely, 2242135531241 is an apocalyptic number.

It is an amenable number.

242135531241 is a deficient number, since it is larger than the sum of its proper divisors (80711843751).

242135531241 is an equidigital number, since it uses as much as digits as its factorization.

242135531241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80711843750.

The product of its digits is 28800, while the sum is 33.

Subtracting from 242135531241 its reverse (142135531242), we obtain a palindrome (99999999999).

The spelling of 242135531241 in words is "two hundred forty-two billion, one hundred thirty-five million, five hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 3 80711843747 242135531241