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2424000115 = 5484800023
BaseRepresentation
bin1001000001111011…
…0100111001110011
320020221011222001001
42100132310321303
514431021000430
61040310422431
7114032442505
oct22036647163
96227158031
102424000115
111034315189
12577961a17
132c826c9c4
1418dd09d75
15e2c173ca
hex907b4e73

2424000115 has 4 divisors (see below), whose sum is σ = 2908800144. Its totient is φ = 1939200088.

The previous prime is 2424000109. The next prime is 2424000151. The reversal of 2424000115 is 5110004242.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2424000115 - 25 = 2424000083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2424000092 and 2424000101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242400007 + ... + 242400016.

It is an arithmetic number, because the mean of its divisors is an integer number (727200036).

Almost surely, 22424000115 is an apocalyptic number.

2424000115 is a deficient number, since it is larger than the sum of its proper divisors (484800029).

2424000115 is an equidigital number, since it uses as much as digits as its factorization.

2424000115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 484800028.

The product of its (nonzero) digits is 320, while the sum is 19.

The square root of 2424000115 is about 49234.1356682536. The cubic root of 2424000115 is about 1343.3140135528.

Adding to 2424000115 its reverse (5110004242), we get a palindrome (7534004357).

The spelling of 2424000115 in words is "two billion, four hundred twenty-four million, one hundred fifteen", and thus it is an aban number.

Divisors: 1 5 484800023 2424000115