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2430302798139 = 3810100932713
BaseRepresentation
bin100011010111011001010…
…101011100000100111011
322121100000222110212021220
4203113121111130010323
5304304230004020024
65100244331203123
7340404111640236
oct43273125340473
98540028425256
102430302798139
1185775a631a07
123330135a64a3
1314823ac050a8
14858ad39c41d
154333edb2e79
hex235d955c13b

2430302798139 has 4 divisors (see below), whose sum is σ = 3240403730856. Its totient is φ = 1620201865424.

The previous prime is 2430302798117. The next prime is 2430302798177. The reversal of 2430302798139 is 9318972030342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2430302798139 - 220 = 2430301749563 is a prime.

It is a super-3 number, since 3×24303027981393 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2430302798091 and 2430302798100.

It is not an unprimeable number, because it can be changed into a prime (2430302798179) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405050466354 + ... + 405050466359.

It is an arithmetic number, because the mean of its divisors is an integer number (810100932714).

Almost surely, 22430302798139 is an apocalyptic number.

2430302798139 is a deficient number, since it is larger than the sum of its proper divisors (810100932717).

2430302798139 is an equidigital number, since it uses as much as digits as its factorization.

2430302798139 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 810100932716.

The product of its (nonzero) digits is 1959552, while the sum is 51.

The spelling of 2430302798139 in words is "two trillion, four hundred thirty billion, three hundred two million, seven hundred ninety-eight thousand, one hundred thirty-nine".

Divisors: 1 3 810100932713 2430302798139