243102554131 has 16 divisors (see below), whose sum is σ = 258821880768. Its totient is φ = 227543500800.

The previous prime is 243102554117. The next prime is 243102554171. The reversal of 243102554131 is 131455201342.

It is a cyclic number.

It is not a de Polignac number, because 243102554131 - 2¹¹ = 243102552083 is a prime.

It is a super-3 number, since 3×243102554131³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243102554093 and 243102554102.

It is not an unprimeable number, because it can be changed into a prime (243102554171) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3004141 + ... + 3084001.

It is an arithmetic number, because the mean of its divisors is an integer number (16176367548).

Almost surely, 2^243102554131 is an apocalyptic number.

243102554131 is a deficient number, since it is larger than the sum of its proper divisors (15719326637).

243102554131 is a wasteful number, since it uses less digits than its factorization.

243102554131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80862.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 243102554131 its reverse (131455201342), we get a palindrome (374557755473).

The spelling of 243102554131 in words is "two hundred forty-three billion, one hundred two million, five hundred fifty-four thousand, one hundred thirty-one".