243112072553411 has 4 divisors (see below), whose sum is σ = 247097516365824. Its totient is φ = 239126628741000.

The previous prime is 243112072553381. The next prime is 243112072553419. The reversal of 243112072553411 is 114355270211342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243112072553411 - 2⁴² = 238714026042307 is a prime.

It is a super-3 number, since 3×243112072553411³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (243112072553419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1992721906115 + ... + 1992721906236.

It is an arithmetic number, because the mean of its divisors is an integer number (61774379091456).

Almost surely, 2^{243112072553411} is an apocalyptic number.

243112072553411 is a deficient number, since it is larger than the sum of its proper divisors (3985443812413).

243112072553411 is an equidigital number, since it uses as much as digits as its factorization.

243112072553411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3985443812412.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 243112072553411 in words is "two hundred forty-three trillion, one hundred twelve billion, seventy-two million, five hundred fifty-three thousand, four hundred eleven".