243113440522451 has 4 divisors (see below), whose sum is σ = 246190825845600. Its totient is φ = 240036055199304.

The previous prime is 243113440522363. The next prime is 243113440522471. The reversal of 243113440522451 is 154225044311342.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 243113440522451 - 2³⁰ = 243112366780627 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243113440522399 and 243113440522408.

It is not an unprimeable number, because it can be changed into a prime (243113440522471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1538692661456 + ... + 1538692661613.

It is an arithmetic number, because the mean of its divisors is an integer number (61547706461400).

Almost surely, 2^{243113440522451} is an apocalyptic number.

243113440522451 is a deficient number, since it is larger than the sum of its proper divisors (3077385323149).

243113440522451 is an equidigital number, since it uses as much as digits as its factorization.

243113440522451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3077385323148.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 243113440522451 its reverse (154225044311342), we get a palindrome (397338484833793).

The spelling of 243113440522451 in words is "two hundred forty-three trillion, one hundred thirteen billion, four hundred forty million, five hundred twenty-two thousand, four hundred fifty-one".