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2431140113 = 17831363511
BaseRepresentation
bin1001000011101000…
…0100000100010001
320021102121201021102
42100322010010101
514434332440423
61041123434145
7114150231023
oct22072040421
96242551242
102431140113
111038351606
1257a225955
132c989c85c
14190c48013
15e3677c28
hex90e84111

2431140113 has 4 divisors (see below), whose sum is σ = 2432505408. Its totient is φ = 2429774820.

The previous prime is 2431140077. The next prime is 2431140119. The reversal of 2431140113 is 3110411342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2431140113 - 210 = 2431139089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2431140119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 679973 + ... + 683538.

It is an arithmetic number, because the mean of its divisors is an integer number (608126352).

Almost surely, 22431140113 is an apocalyptic number.

It is an amenable number.

2431140113 is a deficient number, since it is larger than the sum of its proper divisors (1365295).

2431140113 is a wasteful number, since it uses less digits than its factorization.

2431140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1365294.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 2431140113 is about 49306.5929972859. The cubic root of 2431140113 is about 1344.6316506730.

Adding to 2431140113 its reverse (3110411342), we get a palindrome (5541551455).

The spelling of 2431140113 in words is "two billion, four hundred thirty-one million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 1783 1363511 2431140113