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243114334433 = 4143137898091
BaseRepresentation
bin1110001001101010111…
…1100101100011100001
3212020112001111210200122
43202122233211203201
512440344232200213
6303403555530025
723364412514015
oct3423257454341
9766461453618
10243114334433
1194116781853
123b14a5b9915
1319c05678179
14baa4138545
1564cd586d08
hex389abe58e1

243114334433 has 8 divisors (see below), whose sum is σ = 254835674016. Its totient is φ = 231668791200.

The previous prime is 243114334427. The next prime is 243114334487. The reversal of 243114334433 is 334433411342.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 243114334433 - 210 = 243114333409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243114334393 and 243114334402.

It is not an unprimeable number, because it can be changed into a prime (243114331433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68947283 + ... + 68950808.

It is an arithmetic number, because the mean of its divisors is an integer number (31854459252).

Almost surely, 2243114334433 is an apocalyptic number.

It is an amenable number.

243114334433 is a deficient number, since it is larger than the sum of its proper divisors (11721339583).

243114334433 is a wasteful number, since it uses less digits than its factorization.

243114334433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137898175.

The product of its digits is 124416, while the sum is 35.

Adding to 243114334433 its reverse (334433411342), we get a palindrome (577547745775).

The spelling of 243114334433 in words is "two hundred forty-three billion, one hundred fourteen million, three hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 41 43 1763 137898091 5653821731 5929617913 243114334433