Base | Representation |
---|---|
bin | 1110001001101100101… |
… | …0001010001110110001 |
3 | 212020112112121201012110 |
4 | 3202123022022032301 |
5 | 12440403023103101 |
6 | 303404405115533 |
7 | 23364525645660 |
oct | 3423312121661 |
9 | 766475551173 |
10 | 243121300401 |
11 | 9411a6aa451 |
12 | 3b1509b8ba9 |
13 | 19c06c46a45 |
14 | baa502cdd7 |
15 | 64cdeb0cd6 |
hex | 389b28a3b1 |
243121300401 has 16 divisors (see below), whose sum is σ = 372390095744. Its totient is φ = 138206628864.
The previous prime is 243121300397. The next prime is 243121300403. The reversal of 243121300401 is 104003121342.
It is not a de Polignac number, because 243121300401 - 22 = 243121300397 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (243121300403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29988706 + ... + 29996811.
It is an arithmetic number, because the mean of its divisors is an integer number (23274380984).
Almost surely, 2243121300401 is an apocalyptic number.
243121300401 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
243121300401 is a deficient number, since it is larger than the sum of its proper divisors (129268795343).
243121300401 is a wasteful number, since it uses less digits than its factorization.
243121300401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59985720.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 243121300401 its reverse (104003121342), we get a palindrome (347124421743).
The spelling of 243121300401 in words is "two hundred forty-three billion, one hundred twenty-one million, three hundred thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •