Base | Representation |
---|---|
bin | 1110001001101110101… |
… | …1110110001000111011 |
3 | 212020120011020100111210 |
4 | 3202123223312020323 |
5 | 12440412303143003 |
6 | 303405322254203 |
7 | 23364664005114 |
oct | 3423353661073 |
9 | 766504210453 |
10 | 243130131003 |
11 | 94124690a71 |
12 | 3b153957363 |
13 | 19c08a19256 |
14 | baa628b20b |
15 | 64ceb57503 |
hex | 389baf623b |
243130131003 has 8 divisors (see below), whose sum is σ = 338268008448. Its totient is φ = 155039503784.
The previous prime is 243130131001. The next prime is 243130131029. The reversal of 243130131003 is 300131031342.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 243130131003 - 21 = 243130131001 is a prime.
It is a super-2 number, since 2×2431301310032 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (243130131001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1761812475 + ... + 1761812612.
It is an arithmetic number, because the mean of its divisors is an integer number (42283501056).
Almost surely, 2243130131003 is an apocalyptic number.
243130131003 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
243130131003 is a deficient number, since it is larger than the sum of its proper divisors (95137877445).
243130131003 is a wasteful number, since it uses less digits than its factorization.
243130131003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3523625113.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 243130131003 its reverse (300131031342), we get a palindrome (543261162345).
The spelling of 243130131003 in words is "two hundred forty-three billion, one hundred thirty million, one hundred thirty-one thousand, three".
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