Base | Representation |
---|---|
bin | 1110001001111111011… |
… | …0110001011111010001 |
3 | 212020202000220100222010 |
4 | 3202133312301133101 |
5 | 12441033211320101 |
6 | 303420302133133 |
7 | 23366503531152 |
oct | 3423766613721 |
9 | 766660810863 |
10 | 243200104401 |
11 | 94160134021 |
12 | 3b1732811a9 |
13 | 19c1a378927 |
14 | bab16a3929 |
15 | 64d5d7a2d6 |
hex | 389fdb17d1 |
243200104401 has 4 divisors (see below), whose sum is σ = 324266805872. Its totient is φ = 162133402932.
The previous prime is 243200104339. The next prime is 243200104439. The reversal of 243200104401 is 104401002342.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 243200104401 - 214 = 243200088017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (243200102401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40533350731 + ... + 40533350736.
It is an arithmetic number, because the mean of its divisors is an integer number (81066701468).
Almost surely, 2243200104401 is an apocalyptic number.
It is an amenable number.
243200104401 is a deficient number, since it is larger than the sum of its proper divisors (81066701471).
243200104401 is an equidigital number, since it uses as much as digits as its factorization.
243200104401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81066701470.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 243200104401 its reverse (104401002342), we get a palindrome (347601106743).
The spelling of 243200104401 in words is "two hundred forty-three billion, two hundred million, one hundred four thousand, four hundred one".
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