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243432244113 = 381144081371
BaseRepresentation
bin1110001010110110110…
…0010100001110010001
3212021100012201021210020
43202231230110032101
512442022123302423
6303455313454053
723405322635262
oct3425554241621
9767305637706
10243432244113
119426a179023
123b218b71329
1319c564a6ac6
14bad4450969
1564eb4324e3
hex38adb14391

243432244113 has 4 divisors (see below), whose sum is σ = 324576325488. Its totient is φ = 162288162740.

The previous prime is 243432244079. The next prime is 243432244171. The reversal of 243432244113 is 311442234342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 243432244113 - 214 = 243432227729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (243432244813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40572040683 + ... + 40572040688.

It is an arithmetic number, because the mean of its divisors is an integer number (81144081372).

Almost surely, 2243432244113 is an apocalyptic number.

It is an amenable number.

243432244113 is a deficient number, since it is larger than the sum of its proper divisors (81144081375).

243432244113 is an equidigital number, since it uses as much as digits as its factorization.

243432244113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81144081374.

The product of its digits is 55296, while the sum is 33.

Adding to 243432244113 its reverse (311442234342), we get a palindrome (554874478455).

The spelling of 243432244113 in words is "two hundred forty-three billion, four hundred thirty-two million, two hundred forty-four thousand, one hundred thirteen".

Divisors: 1 3 81144081371 243432244113