Base | Representation |
---|---|
bin | 100011011011001001000… |
… | …010110001000001101011 |
3 | 22121201102020220012000011 |
4 | 203123021002301001223 |
5 | 304340444023410201 |
6 | 5102151352552351 |
7 | 340605554201215 |
oct | 43331102610153 |
9 | 8551366805004 |
10 | 2434324435051 |
11 | 859433754283 |
12 | 3339563b26b7 |
13 | 14872c160cc2 |
14 | 85b715455b5 |
15 | 434c7eae151 |
hex | 236c90b106b |
2434324435051 has 16 divisors (see below), whose sum is σ = 2596254111360. Its totient is φ = 2274520227840.
The previous prime is 2434324435043. The next prime is 2434324435157. The reversal of 2434324435051 is 1505344234342.
It is not a de Polignac number, because 2434324435051 - 23 = 2434324435043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2434324434995 and 2434324435013.
It is not an unprimeable number, because it can be changed into a prime (2434324435031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1089870 + ... + 2460988.
It is an arithmetic number, because the mean of its divisors is an integer number (162265881960).
Almost surely, 22434324435051 is an apocalyptic number.
2434324435051 is a deficient number, since it is larger than the sum of its proper divisors (161929676309).
2434324435051 is a wasteful number, since it uses less digits than its factorization.
2434324435051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1371894.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 2434324435051 its reverse (1505344234342), we get a palindrome (3939668669393).
The spelling of 2434324435051 in words is "two trillion, four hundred thirty-four billion, three hundred twenty-four million, four hundred thirty-five thousand, fifty-one".
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