Base | Representation |
---|---|
bin | 100011011011001010000… |
… | …011001100011001111011 |
3 | 22121201110102200020212000 |
4 | 203123022003030121323 |
5 | 304341012334340121 |
6 | 5102153154552043 |
7 | 340606150563303 |
oct | 43331203143173 |
9 | 8551412606760 |
10 | 2434341324411 |
11 | 85944223a527 |
12 | 33395bb98623 |
13 | 1487327c55c9 |
14 | 85b738a0603 |
15 | 434c96e8526 |
hex | 236ca0cc67b |
2434341324411 has 8 divisors (see below), whose sum is σ = 3606431591760. Its totient is φ = 1622894216256.
The previous prime is 2434341324409. The next prime is 2434341324421. The reversal of 2434341324411 is 1144231434342.
2434341324411 is a `hidden beast` number, since 2 + 43 + 43 + 4 + 132 + 441 + 1 = 666.
2434341324411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2434341324411 - 21 = 2434341324409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2434341324421) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45080394870 + ... + 45080394923.
It is an arithmetic number, because the mean of its divisors is an integer number (450803948970).
Almost surely, 22434341324411 is an apocalyptic number.
2434341324411 is a deficient number, since it is larger than the sum of its proper divisors (1172090267349).
2434341324411 is an equidigital number, since it uses as much as digits as its factorization.
2434341324411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90160789802 (or 90160789796 counting only the distinct ones).
The product of its digits is 110592, while the sum is 36.
Adding to 2434341324411 its reverse (1144231434342), we get a palindrome (3578572758753).
The spelling of 2434341324411 in words is "two trillion, four hundred thirty-four billion, three hundred forty-one million, three hundred twenty-four thousand, four hundred eleven".
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