243441101130113 has 4 divisors (see below), whose sum is σ = 243469610460720. Its totient is φ = 243412591799508.

The previous prime is 243441101130109. The next prime is 243441101130151. The reversal of 243441101130113 is 311031101144342.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 243441101130113 - 2² = 243441101130109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (243441101132113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14254652495 + ... + 14254669572.

It is an arithmetic number, because the mean of its divisors is an integer number (60867402615180).

Almost surely, 2^{243441101130113} is an apocalyptic number.

It is an amenable number.

243441101130113 is a deficient number, since it is larger than the sum of its proper divisors (28509330607).

243441101130113 is an equidigital number, since it uses as much as digits as its factorization.

243441101130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28509330606.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 243441101130113 its reverse (311031101144342), we get a palindrome (554472202274455).

The spelling of 243441101130113 in words is "two hundred forty-three trillion, four hundred forty-one billion, one hundred one million, one hundred thirty thousand, one hundred thirteen".