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243443230433 = 13139134722319
BaseRepresentation
bin1110001010111001011…
…0001110011011100001
3212021100222101110011222
43202232112032123201
512442032431333213
6303500345144425
723405515213334
oct3425626163341
9767328343158
10243443230433
11942753a2227
123b22078b115
1319c588525a0
14bad5ab061b
1564ec3a2808
hex38ae58e6e1

243443230433 has 8 divisors (see below), whose sum is σ = 264055747200. Its totient is φ = 223100158608.

The previous prime is 243443230421. The next prime is 243443230439. The reversal of 243443230433 is 334032344342.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 243443230433 - 222 = 243439036129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 243443230393 and 243443230402.

It is not an unprimeable number, because it can be changed into a prime (243443230439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67359353 + ... + 67362966.

It is an arithmetic number, because the mean of its divisors is an integer number (33006968400).

Almost surely, 2243443230433 is an apocalyptic number.

It is an amenable number.

243443230433 is a deficient number, since it is larger than the sum of its proper divisors (20612516767).

243443230433 is a wasteful number, since it uses less digits than its factorization.

243443230433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134722471.

The product of its (nonzero) digits is 248832, while the sum is 35.

Adding to 243443230433 its reverse (334032344342), we get a palindrome (577475574775).

The spelling of 243443230433 in words is "two hundred forty-three billion, four hundred forty-three million, two hundred thirty thousand, four hundred thirty-three".

Divisors: 1 13 139 1807 134722319 1751390147 18726402341 243443230433