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244033403113 = 503485155871
BaseRepresentation
bin1110001101000110000…
…1100011100011101001
3212022220002220022220101
43203101201203203221
512444240022344423
6304035110425401
723426242462363
oct3432141434351
9768802808811
10244033403113
1194548548745
123b366362261
131a020bba0a6
14bb50219d33
1565340cd7ad
hex38d18638e9

244033403113 has 4 divisors (see below), whose sum is σ = 244518559488. Its totient is φ = 243548246740.

The previous prime is 244033403111. The next prime is 244033403161. The reversal of 244033403113 is 311304330442.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 244033403113 - 21 = 244033403111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (244033403111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242577433 + ... + 242578438.

It is an arithmetic number, because the mean of its divisors is an integer number (61129639872).

Almost surely, 2244033403113 is an apocalyptic number.

It is an amenable number.

244033403113 is a deficient number, since it is larger than the sum of its proper divisors (485156375).

244033403113 is an equidigital number, since it uses as much as digits as its factorization.

244033403113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 485156374.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 244033403113 its reverse (311304330442), we get a palindrome (555337733555).

The spelling of 244033403113 in words is "two hundred forty-four billion, thirty-three million, four hundred three thousand, one hundred thirteen".

Divisors: 1 503 485155871 244033403113