2440433044131 has 16 divisors (see below), whose sum is σ = 3304837536000. Its totient is φ = 1601526678048.

The previous prime is 2440433044111. The next prime is 2440433044177. The reversal of 2440433044131 is 1314403340442.

It is not a de Polignac number, because 2440433044131 - 2⁷ = 2440433044003 is a prime.

It is a super-2 number, since 2×2440433044131² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2440433044092 and 2440433044101.

It is not an unprimeable number, because it can be changed into a prime (2440433044111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4058136 + ... + 4620533.

It is an arithmetic number, because the mean of its divisors is an integer number (206552346000).

Almost surely, 2^{2440433044131} is an apocalyptic number.

2440433044131 is a deficient number, since it is larger than the sum of its proper divisors (864404491869).

2440433044131 is a wasteful number, since it uses less digits than its factorization.

2440433044131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8680138.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 2440433044131 its reverse (1314403340442), we get a palindrome (3754836384573).

The spelling of 2440433044131 in words is "two trillion, four hundred forty billion, four hundred thirty-three million, forty-four thousand, one hundred thirty-one".