Base | Representation |
---|---|
bin | 1011000110110100010111… |
… | …00011111101010001110001 |
3 | 10012110212101111010000021212 |
4 | 11203122023203331101301 |
5 | 11200123340012112423 |
6 | 123540002425325505 |
7 | 5100353505304421 |
oct | 543321343752161 |
9 | 105425344100255 |
10 | 24423525504113 |
11 | 7866a6047748a |
12 | 28a5539336895 |
13 | 1082189621528 |
14 | 606167d62481 |
15 | 2c54a2c4e578 |
hex | 16368b8fd471 |
24423525504113 has 4 divisors (see below), whose sum is σ = 25211381165568. Its totient is φ = 23635669842660.
The previous prime is 24423525504097. The next prime is 24423525504143. The reversal of 24423525504113 is 31140552532442.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 24423525504113 - 24 = 24423525504097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (24423525504143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393927830681 + ... + 393927830742.
It is an arithmetic number, because the mean of its divisors is an integer number (6302845291392).
Almost surely, 224423525504113 is an apocalyptic number.
It is an amenable number.
24423525504113 is a deficient number, since it is larger than the sum of its proper divisors (787855661455).
24423525504113 is an equidigital number, since it uses as much as digits as its factorization.
24423525504113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 787855661454.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 24423525504113 in words is "twenty-four trillion, four hundred twenty-three billion, five hundred twenty-five million, five hundred four thousand, one hundred thirteen".
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