Search a number
-
+
244241214153 = 381413738051
BaseRepresentation
bin1110001101110111101…
…0010010101011001001
3212100102120221020001120
43203131322102223021
513000201222323103
6304111452505453
723434345031436
oct3433572225311
9770376836046
10244241214153
1194644886202
123b403a7b289
131a054c7a7c1
14bb6da72b8d
15654747c253
hex38dde92ac9

244241214153 has 4 divisors (see below), whose sum is σ = 325654952208. Its totient is φ = 162827476100.

The previous prime is 244241214121. The next prime is 244241214169. The reversal of 244241214153 is 351412142442.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 244241214153 - 25 = 244241214121 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (244241214253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40706869023 + ... + 40706869028.

It is an arithmetic number, because the mean of its divisors is an integer number (81413738052).

Almost surely, 2244241214153 is an apocalyptic number.

It is an amenable number.

244241214153 is a deficient number, since it is larger than the sum of its proper divisors (81413738055).

244241214153 is an equidigital number, since it uses as much as digits as its factorization.

244241214153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81413738054.

The product of its digits is 30720, while the sum is 33.

Adding to 244241214153 its reverse (351412142442), we get a palindrome (595653356595).

The spelling of 244241214153 in words is "two hundred forty-four billion, two hundred forty-one million, two hundred fourteen thousand, one hundred fifty-three".

Divisors: 1 3 81413738051 244241214153