Base | Representation |
---|---|
bin | 10110110000110100… |
… | …100101111100111001 |
3 | 2100002100211110002120 |
4 | 112300310211330321 |
5 | 400024000212213 |
6 | 15121144151453 |
7 | 1523452405053 |
oct | 266064457471 |
9 | 70070743076 |
10 | 24441413433 |
11 | a4025a4738 |
12 | 48a1468589 |
13 | 23c68aa918 |
14 | 127c1008d3 |
15 | 980b35423 |
hex | 5b0d25f39 |
24441413433 has 8 divisors (see below), whose sum is σ = 32672328000. Its totient is φ = 16252387248.
The previous prime is 24441413429. The next prime is 24441413441. The reversal of 24441413433 is 33431414442.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 24441413433 - 22 = 24441413429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 24441413394 and 24441413403.
It is not an unprimeable number, because it can be changed into a prime (24441413443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10470733 + ... + 10473066.
It is an arithmetic number, because the mean of its divisors is an integer number (4084041000).
Almost surely, 224441413433 is an apocalyptic number.
It is an amenable number.
24441413433 is a deficient number, since it is larger than the sum of its proper divisors (8230914567).
24441413433 is a wasteful number, since it uses less digits than its factorization.
24441413433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20944191.
The product of its digits is 55296, while the sum is 33.
Adding to 24441413433 its reverse (33431414442), we get a palindrome (57872827875).
The spelling of 24441413433 in words is "twenty-four billion, four hundred forty-one million, four hundred thirteen thousand, four hundred thirty-three".
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