2450113331 has 4 divisors (see below), whose sum is σ = 2452542600. Its totient is φ = 2447684064.

The previous prime is 2450113319. The next prime is 2450113361. The reversal of 2450113331 is 1333110542.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2450113331 is a prime.

It is a super-3 number, since 3×2450113331³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2450113297 and 2450113306.

It is not an unprimeable number, because it can be changed into a prime (2450113361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1213121 + ... + 1215138.

It is an arithmetic number, because the mean of its divisors is an integer number (613135650).

Almost surely, 2^2450113331 is an apocalyptic number.

2450113331 is a deficient number, since it is larger than the sum of its proper divisors (2429269).

2450113331 is a wasteful number, since it uses less digits than its factorization.

2450113331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2429268.

The product of its (nonzero) digits is 1080, while the sum is 23.

The square root of 2450113331 is about 49498.6194857998. The cubic root of 2450113331 is about 1348.1205361651.

Adding to 2450113331 its reverse (1333110542), we get a palindrome (3783223873).

The spelling of 2450113331 in words is "two billion, four hundred fifty million, one hundred thirteen thousand, three hundred thirty-one".