Base | Representation |
---|---|
bin | 1110010000110110001… |
… | …1000001100100000001 |
3 | 212102111021210010220122 |
4 | 3210031203001210001 |
5 | 13003320321433441 |
6 | 304323042350025 |
7 | 23463221133056 |
oct | 3441543014401 |
9 | 772437703818 |
10 | 245040421121 |
11 | 94a14a25231 |
12 | 3b5a765b315 |
13 | 1a151713732 |
14 | bc07c7302d |
15 | 65926e934b |
hex | 390d8c1901 |
245040421121 has 4 divisors (see below), whose sum is σ = 246543736752. Its totient is φ = 243537105492.
The previous prime is 245040421033. The next prime is 245040421189. The reversal of 245040421121 is 121124040542.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 245040421121 - 214 = 245040404737 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (245040921121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 751657571 + ... + 751657896.
It is an arithmetic number, because the mean of its divisors is an integer number (61635934188).
Almost surely, 2245040421121 is an apocalyptic number.
It is an amenable number.
245040421121 is a deficient number, since it is larger than the sum of its proper divisors (1503315631).
245040421121 is a wasteful number, since it uses less digits than its factorization.
245040421121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1503315630.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 245040421121 its reverse (121124040542), we get a palindrome (366164461663).
It can be divided in two parts, 245040421 and 121, that added together give a palindrome (245040542).
The spelling of 245040421121 in words is "two hundred forty-five billion, forty million, four hundred twenty-one thousand, one hundred twenty-one".
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