Base | Representation |
---|---|
bin | 1110010001100010001… |
… | …1100110010110000001 |
3 | 212102222011022212201120 |
4 | 3210120203212112001 |
5 | 13004210112334103 |
6 | 304353241222453 |
7 | 23500623065115 |
oct | 3443043462601 |
9 | 772864285646 |
10 | 245225121153 |
11 | 94aaa208091 |
12 | 3b639491a29 |
13 | 1a180a719ac |
14 | bc245d1745 |
15 | 65a3a30253 |
hex | 39188e6581 |
245225121153 has 4 divisors (see below), whose sum is σ = 326966828208. Its totient is φ = 163483414100.
The previous prime is 245225121139. The next prime is 245225121191. The reversal of 245225121153 is 351121522542.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 245225121153 - 25 = 245225121121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (245225521153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40870853523 + ... + 40870853528.
It is an arithmetic number, because the mean of its divisors is an integer number (81741707052).
Almost surely, 2245225121153 is an apocalyptic number.
It is an amenable number.
245225121153 is a deficient number, since it is larger than the sum of its proper divisors (81741707055).
245225121153 is an equidigital number, since it uses as much as digits as its factorization.
245225121153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81741707054.
The product of its digits is 24000, while the sum is 33.
Adding to 245225121153 its reverse (351121522542), we get a palindrome (596346643695).
The spelling of 245225121153 in words is "two hundred forty-five billion, two hundred twenty-five million, one hundred twenty-one thousand, one hundred fifty-three".
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