Base | Representation |
---|---|
bin | 110111110011000011110111… |
… | …100010111010110010101001 |
3 | 1012011220010220211011010002212 |
4 | 313303003313202322302221 |
5 | 224131124034031102223 |
6 | 2225531503210534505 |
7 | 102455444400461414 |
oct | 6763036742726251 |
9 | 1164803824133085 |
10 | 245401404550313 |
11 | 712131732a3760 |
12 | 23634529a37435 |
13 | a6c133a23b89b |
14 | 44856c43c2b7b |
15 | 1d586c1369278 |
hex | df30f78baca9 |
245401404550313 has 16 divisors (see below), whose sum is σ = 267937927814592. Its totient is φ = 222902771520000.
The previous prime is 245401404550283. The next prime is 245401404550327. The reversal of 245401404550313 is 313055404104542.
It is not a de Polignac number, because 245401404550313 - 240 = 244301892922537 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (245401404550373) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1111344245 + ... + 1111565037.
It is an arithmetic number, because the mean of its divisors is an integer number (16746120488412).
Almost surely, 2245401404550313 is an apocalyptic number.
It is an amenable number.
245401404550313 is a deficient number, since it is larger than the sum of its proper divisors (22536523264279).
245401404550313 is a wasteful number, since it uses less digits than its factorization.
245401404550313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306136.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 245401404550313 its reverse (313055404104542), we get a palindrome (558456808654855).
The spelling of 245401404550313 in words is "two hundred forty-five trillion, four hundred one billion, four hundred four million, five hundred fifty thousand, three hundred thirteen".
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