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245553511414011 = 381851170471337
BaseRepresentation
bin110111110101010001100001…
…110100100011100011111011
31012012102200112102001101122020
4313311101201310203203323
5224141122042410222021
62230125420440525523
7102502440631464423
oct6765214164434373
91165380472041566
10245553511414011
1171271728698779
1223659aba1808a3
13a70279b140048
14448cbd38c9483
151d5c624db97c6
hexdf5461d238fb

245553511414011 has 4 divisors (see below), whose sum is σ = 327404681885352. Its totient is φ = 163702340942672.

The previous prime is 245553511413997. The next prime is 245553511414051. The reversal of 245553511414011 is 110414115355542.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 245553511414011 - 27 = 245553511413883 is a prime.

It is not an unprimeable number, because it can be changed into a prime (245553511414051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40925585235666 + ... + 40925585235671.

It is an arithmetic number, because the mean of its divisors is an integer number (81851170471338).

Almost surely, 2245553511414011 is an apocalyptic number.

245553511414011 is a deficient number, since it is larger than the sum of its proper divisors (81851170471341).

245553511414011 is an equidigital number, since it uses as much as digits as its factorization.

245553511414011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81851170471340.

The product of its (nonzero) digits is 240000, while the sum is 42.

Adding to 245553511414011 its reverse (110414115355542), we get a palindrome (355967626769553).

The spelling of 245553511414011 in words is "two hundred forty-five trillion, five hundred fifty-three billion, five hundred eleven million, four hundred fourteen thousand, eleven".

Divisors: 1 3 81851170471337 245553511414011