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246225041113 = 1559157937807
BaseRepresentation
bin1110010101010000100…
…1111111011011011001
3212112112211212002001011
43211110021333123121
513013232102303423
6305040401053521
723534454213502
oct3452411773331
9775484762034
10246225041113
1195472686817
123b8783272a1
131a2acc815cc
14bcbb31bba9
1566116e7b0d
hex395427f6d9

246225041113 has 4 divisors (see below), whose sum is σ = 246382980480. Its totient is φ = 246067101748.

The previous prime is 246225041033. The next prime is 246225041119. The reversal of 246225041113 is 311140522642.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-246225041113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (246225041119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78967345 + ... + 78970462.

It is an arithmetic number, because the mean of its divisors is an integer number (61595745120).

Almost surely, 2246225041113 is an apocalyptic number.

It is an amenable number.

246225041113 is a deficient number, since it is larger than the sum of its proper divisors (157939367).

246225041113 is a wasteful number, since it uses less digits than its factorization.

246225041113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157939366.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 246225041113 its reverse (311140522642), we get a palindrome (557365563755).

The spelling of 246225041113 in words is "two hundred forty-six billion, two hundred twenty-five million, forty-one thousand, one hundred thirteen".

Divisors: 1 1559 157937807 246225041113