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2481110113 = 5994142087
BaseRepresentation
bin1001001111100010…
…1011110001100001
320101220122110020011
42103320223301201
520040131010423
61050110444521
7115325042116
oct22370536141
96356573204
102481110113
111063581829
12592b03741
133070473c1
1419773490d
15e7c48b0d
hex93e2bc61

2481110113 has 4 divisors (see below), whose sum is σ = 2485252800. Its totient is φ = 2476967428.

The previous prime is 2481110089. The next prime is 2481110153. The reversal of 2481110113 is 3110111842.

2481110113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2481110113 - 25 = 2481110081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2481110153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2070445 + ... + 2071642.

It is an arithmetic number, because the mean of its divisors is an integer number (621313200).

Almost surely, 22481110113 is an apocalyptic number.

It is an amenable number.

2481110113 is a deficient number, since it is larger than the sum of its proper divisors (4142687).

2481110113 is an equidigital number, since it uses as much as digits as its factorization.

2481110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4142686.

The product of its (nonzero) digits is 192, while the sum is 22.

The square root of 2481110113 is about 49810.7429476815. The cubic root of 2481110113 is about 1353.7818262391.

Adding to 2481110113 its reverse (3110111842), we get a palindrome (5591221955).

The spelling of 2481110113 in words is "two billion, four hundred eighty-one million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 599 4142087 2481110113