Base | Representation |
---|---|
bin | 1110011111110000000… |
… | …0100001100110010011 |
3 | 212210211002211022101210 |
4 | 3213330000201212103 |
5 | 13040014012210143 |
6 | 310224035431203 |
7 | 23664320460003 |
oct | 3477400414623 |
9 | 783732738353 |
10 | 249041131923 |
11 | 966882544a1 |
12 | 40323455503 |
13 | 1a63b52382c |
14 | c0a7330003 |
15 | 6728a60033 |
hex | 39fc021993 |
249041131923 has 18 divisors (see below), whose sum is σ = 347147424484. Its totient is φ = 158796160424.
The previous prime is 249041131903. The next prime is 249041131987. The reversal of 249041131923 is 329131140942.
It is not a de Polignac number, because 249041131923 - 25 = 249041131891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (249041131903) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 19874086 + ... + 19886612.
Almost surely, 2249041131923 is an apocalyptic number.
249041131923 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
249041131923 is a deficient number, since it is larger than the sum of its proper divisors (98106292561).
249041131923 is an frugal number, since it uses more digits than its factorization.
249041131923 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25103 (or 12553 counting only the distinct ones).
The product of its (nonzero) digits is 46656, while the sum is 39.
The spelling of 249041131923 in words is "two hundred forty-nine billion, forty-one million, one hundred thirty-one thousand, nine hundred twenty-three".
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