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25001121241 = 29862107629
BaseRepresentation
bin10111010010001011…
…101101010111011001
32101112101000112212101
4113102023231113121
5402200241334431
615252500443401
71543360011205
oct272213552731
971471015771
1025001121241
11a66a532478
124a189a9561
132485839985
1412d2599b05
159b4d44961
hex5d22ed5d9

25001121241 has 4 divisors (see below), whose sum is σ = 25863228900. Its totient is φ = 24139013584.

The previous prime is 25001121227. The next prime is 25001121251. The reversal of 25001121241 is 14212110052.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18055565641 + 6945555600 = 134371^2 + 83340^2 .

It is a cyclic number.

It is not a de Polignac number, because 25001121241 - 25 = 25001121209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25001121251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431053786 + ... + 431053843.

It is an arithmetic number, because the mean of its divisors is an integer number (6465807225).

Almost surely, 225001121241 is an apocalyptic number.

It is an amenable number.

25001121241 is a deficient number, since it is larger than the sum of its proper divisors (862107659).

25001121241 is an equidigital number, since it uses as much as digits as its factorization.

25001121241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 862107658.

The product of its (nonzero) digits is 160, while the sum is 19.

Adding to 25001121241 its reverse (14212110052), we get a palindrome (39213231293).

The spelling of 25001121241 in words is "twenty-five billion, one million, one hundred twenty-one thousand, two hundred forty-one".

Divisors: 1 29 862107629 25001121241