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2500534081 = 11311221071
BaseRepresentation
bin1001010100001011…
…0001111101000001
320110021012021220101
42111002301331001
520110114042311
61052043042401
7115652121553
oct22502617501
96407167811
102500534081
1110735392a1
12599510401
1330b088586
1419a14d4d3
15e97d3ec1
hex950b1f41

2500534081 has 4 divisors (see below), whose sum is σ = 2500766464. Its totient is φ = 2500301700.

The previous prime is 2500534067. The next prime is 2500534147. The reversal of 2500534081 is 1804350052.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2500534081 - 211 = 2500532033 is a prime.

It is a super-2 number, since 2×25005340812 = 12505341380485029122, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2500534061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99225 + ... + 121846.

It is an arithmetic number, because the mean of its divisors is an integer number (625191616).

Almost surely, 22500534081 is an apocalyptic number.

It is an amenable number.

2500534081 is a deficient number, since it is larger than the sum of its proper divisors (232383).

2500534081 is a wasteful number, since it uses less digits than its factorization.

2500534081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232382.

The product of its (nonzero) digits is 4800, while the sum is 28.

The square root of 2500534081 is about 50005.3405247879. The cubic root of 2500534081 is about 1357.3054493409.

The spelling of 2500534081 in words is "two billion, five hundred million, five hundred thirty-four thousand, eighty-one".

Divisors: 1 11311 221071 2500534081