Base | Representation |
---|---|
bin | 1001010100001011… |
… | …0001111101000001 |
3 | 20110021012021220101 |
4 | 2111002301331001 |
5 | 20110114042311 |
6 | 1052043042401 |
7 | 115652121553 |
oct | 22502617501 |
9 | 6407167811 |
10 | 2500534081 |
11 | 10735392a1 |
12 | 599510401 |
13 | 30b088586 |
14 | 19a14d4d3 |
15 | e97d3ec1 |
hex | 950b1f41 |
2500534081 has 4 divisors (see below), whose sum is σ = 2500766464. Its totient is φ = 2500301700.
The previous prime is 2500534067. The next prime is 2500534147. The reversal of 2500534081 is 1804350052.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2500534081 - 211 = 2500532033 is a prime.
It is a super-2 number, since 2×25005340812 = 12505341380485029122, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2500534061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99225 + ... + 121846.
It is an arithmetic number, because the mean of its divisors is an integer number (625191616).
Almost surely, 22500534081 is an apocalyptic number.
It is an amenable number.
2500534081 is a deficient number, since it is larger than the sum of its proper divisors (232383).
2500534081 is a wasteful number, since it uses less digits than its factorization.
2500534081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 232382.
The product of its (nonzero) digits is 4800, while the sum is 28.
The square root of 2500534081 is about 50005.3405247879. The cubic root of 2500534081 is about 1357.3054493409.
The spelling of 2500534081 in words is "two billion, five hundred million, five hundred thirty-four thousand, eighty-one".
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