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2500630147 = 171923773257
BaseRepresentation
bin1001010100001100…
…1001011010000011
320110021101011200101
42111003021122003
520110130131042
61052045103231
7115653001621
oct22503113203
96407334611
102500630147
1110735a4494
12599557b17
1330b0c0212
1419a176511
15e98026b7
hex950c9683

2500630147 has 16 divisors (see below), whose sum is σ = 2789108640. Its totient is φ = 2228041728.

The previous prime is 2500630123. The next prime is 2500630177. The reversal of 2500630147 is 7410360052.

It is a cyclic number.

It is not a de Polignac number, because 2500630147 - 211 = 2500628099 is a prime.

It is a super-2 number, since 2×25006301472 = 12506302264170483218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2500630117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 766143 + ... + 769399.

It is an arithmetic number, because the mean of its divisors is an integer number (174319290).

Almost surely, 22500630147 is an apocalyptic number.

2500630147 is a deficient number, since it is larger than the sum of its proper divisors (288478493).

2500630147 is a wasteful number, since it uses less digits than its factorization.

2500630147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5670.

The product of its (nonzero) digits is 5040, while the sum is 28.

The square root of 2500630147 is about 50006.3010729648. The cubic root of 2500630147 is about 1357.3228308590.

Adding to 2500630147 its reverse (7410360052), we get a palindrome (9910990199).

The spelling of 2500630147 in words is "two billion, five hundred million, six hundred thirty thousand, one hundred forty-seven".

Divisors: 1 17 19 323 2377 3257 40409 45163 55369 61883 767771 1052011 7741889 131612113 147095891 2500630147