Base | Representation |
---|---|
bin | 100100011100001010011… |
… | …000100010111001010011 |
3 | 22212101121211110110202101 |
4 | 210130022120202321103 |
5 | 312011434333440430 |
6 | 5154215221501231 |
7 | 345626632663645 |
oct | 44341230427123 |
9 | 8771554413671 |
10 | 2504140140115 |
11 | 885aaa90a889 |
12 | 34539b571817 |
13 | 1521a735c8a3 |
14 | 892b58a6895 |
15 | 45212318dca |
hex | 2470a622e53 |
2504140140115 has 4 divisors (see below), whose sum is σ = 3004968168144. Its totient is φ = 2003312112088.
The previous prime is 2504140140113. The next prime is 2504140140137. The reversal of 2504140140115 is 5110410414052.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2504140140115 - 21 = 2504140140113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2504140140113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250414014007 + ... + 250414014016.
It is an arithmetic number, because the mean of its divisors is an integer number (751242042036).
Almost surely, 22504140140115 is an apocalyptic number.
2504140140115 is a deficient number, since it is larger than the sum of its proper divisors (500828028029).
2504140140115 is an equidigital number, since it uses as much as digits as its factorization.
2504140140115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500828028028.
The product of its (nonzero) digits is 3200, while the sum is 28.
Adding to 2504140140115 its reverse (5110410414052), we get a palindrome (7614550554167).
The spelling of 2504140140115 in words is "two trillion, five hundred four billion, one hundred forty million, one hundred forty thousand, one hundred fifteen".
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