Search a number
-
+
25061424125131 = 30103832522477
BaseRepresentation
bin1011011001011000100010…
…10010000101010011001011
310021201211220201220111020101
411230230101102011103023
511241101244034001011
6125145020450510231
75164425311154052
oct554542122052313
9107654821814211
1025061424125131
117a92543628979
1229890a4295377
1310ca388b7c874
14628d9d689399
152d6d89d682c1
hex16cb114854cb

25061424125131 has 4 divisors (see below), whose sum is σ = 25062256677712. Its totient is φ = 25060591572552.

The previous prime is 25061424125123. The next prime is 25061424125149. The reversal of 25061424125131 is 13152142416052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25061424125131 - 23 = 25061424125123 is a prime.

It is a super-2 number, since 2×250614241251312 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25061424135131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416231136 + ... + 416291341.

It is an arithmetic number, because the mean of its divisors is an integer number (6265564169428).

Almost surely, 225061424125131 is an apocalyptic number.

25061424125131 is a deficient number, since it is larger than the sum of its proper divisors (832552581).

25061424125131 is an equidigital number, since it uses as much as digits as its factorization.

25061424125131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 832552580.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 25061424125131 in words is "twenty-five trillion, sixty-one billion, four hundred twenty-four million, one hundred twenty-five thousand, one hundred thirty-one".

Divisors: 1 30103 832522477 25061424125131