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25106993 = 31809903
BaseRepresentation
bin101111111000…
…1101000110001
31202020120022122
41133301220301
522411410433
62254044025
7423256142
oct137615061
952216278
1025106993
111319928a
1284a9615
135280b12
143497ac9
15230e198
hex17f1a31

25106993 has 4 divisors (see below), whose sum is σ = 25916928. Its totient is φ = 24297060.

The previous prime is 25106987. The next prime is 25107013. The reversal of 25106993 is 39960152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25106993 is a prime.

It is a super-2 number, since 2×251069932 = 1260722195004098, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25106903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 404921 + ... + 404982.

It is an arithmetic number, because the mean of its divisors is an integer number (6479232).

Almost surely, 225106993 is an apocalyptic number.

It is an amenable number.

25106993 is a deficient number, since it is larger than the sum of its proper divisors (809935).

25106993 is an equidigital number, since it uses as much as digits as its factorization.

25106993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 809934.

The product of its (nonzero) digits is 14580, while the sum is 35.

The square root of 25106993 is about 5010.6878769287. The cubic root of 25106993 is about 292.8183127351.

The spelling of 25106993 in words is "twenty-five million, one hundred six thousand, nine hundred ninety-three".

Divisors: 1 31 809903 25106993